You have two spinners in front of you. Spinner “A” contains two spaces each of the numbers one, two, and three. Spinner “B” contains six spaces with one deuce each. You have spun both spinners 12 times each. Which one is more likely to give you a sum of 24 under these circumstances?
2006-10-01 14:04:45 · 11 answers · asked by blooutflash 3 in Science & Mathematics ➔ Mathematics
I would have to go with spinner B because that seems to have the better chance of giving a number like 24 under these circumstances.
2006-10-01 14:07:27 · answer #1 · answered by Anonymous · 1⤊ 0⤋
The first spinner (A) is divided as follows:
1, 1, 2, 2, 3, 3.
The expected spin on spinner A is (1 + 1 + 2 + 2 + 3 + 3) / 6 or 2.
The second spinner (B) is divided as follows:
2, 2, 2, 2, 2, 2
The expected spin on spinner B is (2 + 2 + 2 + 2 + 2 + 2) / 6 or 2.
So both spinners are *expected* to return 24 after 12 spins.
However, spinner B is *guaranteed* to give you a sum of 24, while spinner A is *likely* to give you a sum of 24.
So B is the right answer.
2006-10-01 21:08:27 · answer #2 · answered by cg-productions 4 · 5⤊ 0⤋
The second spinner has only 2's on it? If so, then if you spin it 12 times, you will always get 24, therefore the likelihood of getting a sum 24 with spinner two is 100%.
Therefore, the second spinner has a higher likelihood of giving you a sum of 24 (because, for example if you hit all 1's you'd get 12, if you hit 6 1's and 6 2's you'd get 18, etc. I'll leave it to you to figure out the exact probability of getting a sum of 24 on the first spinner, but it's clearly less than 100%.)
2006-10-01 21:06:18 · answer #3 · answered by I ♥ AUG 6 · 4⤊ 0⤋
If your question means what I think it means, the probability is 1 for Spinner B, and less than 1 for Spinner A, so the answer is Spinner B.
2006-10-01 21:11:56 · answer #4 · answered by actuator 5 · 0⤊ 0⤋
Hi. Spinner B. Did I win?
2006-10-01 21:06:53 · answer #5 · answered by Cirric 7 · 0⤊ 0⤋
um unless i am reading this wrong, spinners are basically dice?
Die A = 1,1,2,2,3,3 for its six sides
Die B = 2,2,2,2,2,2 for its six sides
they are both rolled 12 times and for each roll the outcome was marked and added to the next one and so forth...well it appears pretty obvious...
if u rolled Die A 12 times and every time it hit (1) u'd only get 12 as ur total.
if u rolled Die B 12 times and it all has (2) on every side 2x12=24
this is so easy which makes me thing i'm missing something in the question...???
2006-10-01 21:14:00 · answer #6 · answered by Anonymous · 0⤊ 0⤋
spinner B
2006-10-01 21:10:52 · answer #7 · answered by defleppard 3 · 0⤊ 0⤋
I'm braindead at the moment lol
2006-10-01 21:06:20 · answer #8 · answered by NO♥NAME 5 · 0⤊ 1⤋
I dont get that one duece each part. So im stuck.
2006-10-01 21:06:56 · answer #9 · answered by Anonymous · 0⤊ 1⤋
your directions are confusing, try getting a picture which i no is impossible or be more clear, im kinda getting a picture but still no cigar
2006-10-01 21:07:29 · answer #10 · answered by tonyma90 4 · 0⤊ 2⤋