What is balls horizontal displacement?

Question

initial velocity of 29.4 with initial angle of 30 degrees in trejectory for 3 secondsHaving issues with finding the right formulas? what is balls horizontal displacement?

how would I figure out maximum vertical displacement also?

Thank you Scoot ur advice helped alot it is actually 76.4 (cos30 times 29.4 times 3 seconds) you got me going in the right direction though? I hate word probelms

Answer 1

scoot's answer was close.
29.4 x cos 30 degrees gives you the horizontal velocity (which does not change, since gravity does not act in a horizontal direction).

cos 30 degrees is sqrt(3) / 2. Calculate that number and multiply it by 29.4 (as shown above) ti get the horizontal velocity.

Multiply the horizontal velocity (in distance units per second) by 3 seconds to determine the horizontal displacement after 3 seconds.

Maximum vertical displacement:
This isn't how your physics (or calculus) teacher would have you do it, but here's an easy way to figure it out.
1. Calculate initial vertical velocity = 29.4 x sin 30 deg (hope you understand why this is the formula) = 29.4 x 0.5 = 14.7
(You didn't specify the units, but I'll assume that they are feet per second.)
2. Now figure how long it will take for the vertical velocity to decrease to 0. Gravity is slowing the vertical velocity by 32 feet per sec every second ("32 feet per sec per sec" or 32 ft/sec^2). So it will take (14.7 / 32) sec for the vertical component of the velocity to reach 0. (And after that, the ball does not go any higher, so the highest point is reached (14.7 / 32) sec after launch.)
3. During this period of time, the vertical velocity decreases from 14.7 to 0, so the average velocity is (14.7 + 0) / 2 = 7.35 ft/sec.
4. The ball travels for (14.7 / 32) sec (step 2.) at an average vertical velocity of 7.35 ft/sec (step 3.). So the distance it rises is 7.35 x (14.7 / 32). Calculate that number and you'll have the maximum height.

Here's how your physics teacher would have you do it:
time = 32/14.7
distance = g x t^2 / 2 = 32 x (32/14.7)^2 / 2

Good luck!

Answer 2

The ball's horizontal displacement is known as Range of the projectile.
So, the formula for range is: R = u^2/g sin2@ (@ = angle of projection)
Therefore, R = (29.4)(29.4)/9.8 sin2(30)
R = (88.2) sin 60
R = (88.2) (0.866)
R = 76.38 m

Maximum vertical displacement is same as maximum height reached by the projected body, so its formula is:
H = u^2/2g sin^2 @
H = (29.4)(29.4)/(2)(9.8) sin^2 (30)
H = (44.1)(1/4) [Since sin30 = 1/2, and sin^2 (30) = 1/4]
H = 11.025 m

Answer 3

77.5units with trigonemetric what nots i think try cosine of 30 times x over 29.4

Answer 4

angle of dangle, is propotionate to heat of the meat.