A landscaping company placed two orders with a nursery. The first order was for 13 bushes and 4 trees, and totalled $487. The second order was for 6 bushes and 2 trees, and totalled $237. The bill does not list the per-item price. What is the cost of one bush and one tree?
Can you give me the two equations and the cost of one bush and one tree?
2006-10-01 12:48:51 · 3 answers · asked by Danyizzle 4 in Education & Reference ➔ Homework Help
bush = x, tree = y
Therefore,
(i) 13x + 4y = 487
(ii) 6x + 2y = 237
From (i) x = (487 - 4y) / 13
From (ii) x = (237 - 2y) / 6
You should be able to resolve x & y from the above.
The answer:
1 bush = $13 and 1 tree = $79.50
2006-10-01 13:06:22 · answer #1 · answered by nayrah1974_zu 2 · 0⤊ 0⤋
1. Let x = a bush and y = a tree.
Therefore 13x + 4y =487 [ 1 ]
and 6x+ 2y = 237 [ 2 ]
By subtraction 1 minus 2
7x + 2y = 250 { 3 ]
By subtraction 3 minus 2
x = 13.
By applying the value of 13 for x in all three formulae the value
of y is equal to 79.5.
Thus one bush costs 13$ and one tree costs 79.5$.
Hope this helps.
2006-10-01 13:21:18 · answer #2 · answered by Whacker 1 · 0⤊ 0⤋
13b + 4t = 487
6b + 2t = 237
Multiply the second equation by two, then subtract the two.
You get: b = 13
Substituting back in, you get: 59/2 or 29.50 for t.
2006-10-01 12:57:42 · answer #3 · answered by Link 5 · 0⤊ 0⤋