Try +12 and -5
2006-10-01 12:14:54
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answer #1
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answered by tlf 3
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Another approach is to consider the factors of 60
1, 60, 2, 30, 3, 20, 4, 15, 5, 12, 6, 10
Only the 5, 12 pair can be used to add to 7
-5 and 12
2006-10-01 20:27:19
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answer #2
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answered by kindricko 7
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x+y=7 gives x=(7-y)
Substitute this in the second equation. We get
(7-y)*(y)=-60, i.e.,
7y - y^2 =-60, or
y^2 -7y - 60=0
y^2 -12y +5y - 60=0
y(y-12) +5(y-12) =0
Thus (y-12)*(y+5)=0
This gives two solutions
y = 12
and
y = - 5
With y=12, we get x= - 5, and with y= -5, we get x = 12
Thus there are two solutions
x = -5 , y = 12
and
x = 12, y = -5
2006-10-01 19:23:47
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answer #3
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answered by curious 4
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x + y = 7
x * y = -60
x + y = 7
y = -x + 7
x(-x + 7) = -60
-x^2 + 7x = -60
x^2 - 7x - 60 = 0
(x - 12)(x + 5) = 0
x = 12 or -5
y = -x + 7
y = -(12 or -5) + 7
y = (-12 or 5) + 7
y = -5 or 12
ANS : 12 and -5
2006-10-02 00:16:36
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answer #4
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answered by Sherman81 6
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x+y=7
y=-x+7
x*y=-60
x*(-x+7)=-60
-x^2+7x=-60
-x^2+7x+60=0
Quadratic Equation
x=[-b+SQRT(b^2-4ac)]/2a and x=[-b-SQRT(b^2-4ac)]/2a
x=[-7+SQRT(7^2-(4)(-1)(60))]/2*(-1) and x=[-7-SQRT(7^2-(4)(-1)(60))]/2*(-1)
x=[-7+SQRT(49+240)/(-2) and x=[-7-SQRT(49+240)/(-2)
x={-7+SQRT(289)/(-2) and x={-7-SQRT(289)/(-2)
x=(-7+17)/(-2) and x=(-7-17)/(-2)
x=-10/(-2) and x=-24/(-2)
x=-5 and x=12
x+y=7
-5+y=7 or 12+y=7
y=12 or y=-5
2006-10-01 19:52:44
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answer #5
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answered by Karl 2
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-5 and 12
you can do the rest of your homework yourself!
2006-10-01 19:21:19
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answer #6
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answered by silentnonrev 7
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