Place one or more sets of parentheses in the expression on the left side of each equation so that the resulting equation is true.
6+1sqared-20=29
11+6-3squared=20
stumped! any hints or clues would be helpful. i don't see anywhere you could put the parantheses and get that answer.
2006-10-01 11:07:06 · 7 answers · asked by xsugarxnspicex 3 in Education & Reference ➔ Homework Help
(6+1)squared-20=29=49-20
11+(6-3)squared=20=11+9
There are only a few possibilities for each, check them out.
for the first one, 6+(1squared) would only be 7, so if you subtract 20 it becomes negative, so you needed to have a bigger square.
And the only possibility was (6+1)squared.
2006-10-01 11:13:34 · answer #1 · answered by smci 7 · 0⤊ 0⤋
((6+1)squared)-20 = (7squared)-20 = 49-20 = 29
11+((6-3)squared) = 11 + (3squared) = 11 + 9 = 20
2006-10-01 11:13:52 · answer #2 · answered by David Y 5 · 0⤊ 0⤋
not that difficult if you try different combinations,
(6 + 1)^2 - 20 = 49-20= 29
11 + (6-3)^2 = 11 + 9 = 20
Good luck!
2006-10-01 11:31:03 · answer #3 · answered by alrivera_1 4 · 0⤊ 0⤋
(6+1)squared-20 = 29
11+(6-3)squared = 20
2006-10-01 11:14:59 · answer #4 · answered by grisgris0905 3 · 0⤊ 0⤋
(6+1) squared-20=29
49-20=29
11+(6-3)squared=20
11+9=20
Have fun with math!!
2006-10-01 11:15:50 · answer #5 · answered by heyheyhey 4 · 0⤊ 0⤋
(6+1)^2 - 20=29
11+(6-3)^2=20
2006-10-01 11:15:27 · answer #6 · answered by honeybun 4 · 0⤊ 0⤋
i have no idea wow thst hardd
2006-10-01 11:12:43 · answer #7 · answered by Anonymous · 0⤊ 0⤋