I am studying "solving systems of equations in 3 variable" I understand how to work them out but on the same work sheet they give me this word problem: the sum of three numbers is 6. the third number is the sum of the first and second numbers. The first number is one more than the third number. find the numbers.
I am trying to set it up as an 3 equations and this is all i can think of : x+y+z =6
z =(x+y)
x+1= z
Is this is correct way to set this problem up? PLEASE HELP
2006-10-01 10:55:37 · 4 answers · asked by taterbug121990 2 in Education & Reference ➔ Homework Help
Because the first number is one more that the third number that would imply that z + 1 = x or x - 1 = z.
So you have the three equations:
x + y + z = 6
x + y = z
x - 1 = z
From there you should be able to solve it on your own!
Good Luck.
2006-10-01 11:08:55 · answer #1 · answered by merfie 2 · 0⤊ 0⤋
the first two equations are correct. The third equation should read:
x=z+1
2006-10-01 17:58:36 · answer #2 · answered by Keith P 1 · 0⤊ 0⤋
so ...
x = z +1
z = x - 1 = x + y
y = -1
so
x + (-1) + (x - 1) = 6
2x -2 = 6
2x = 8
x = 4
so
4 + (-1) + z = 6
3 + z = 6
z = 3
2006-10-01 18:12:04 · answer #3 · answered by Anonymous · 0⤊ 1⤋
the first part is correct. The second part should be x-1=z
2006-10-01 17:58:54 · answer #4 · answered by Amy Dee 2 · 0⤊ 1⤋