fraction in the simplest form?
40x2nd powery/55x2nd power3y=
2006-10-01 09:08:38 · 6 answers · asked by lovinmymatt 2 in Science & Mathematics ➔ Mathematics
x^2 cancels along with the y, so you have
40/(55*3)
Both 40 and 55 are divisible by 5, so you have
8/(11*3) = 8/33
2006-10-01 09:12:35 · answer #1 · answered by MsMath 7 · 0⤊ 0⤋
You have 40x^2 y / (55x^2 3y), assuming I'm interpreting what you typed correctly, though it seems strangely written. Cancel the x^2's and y and get
40 / (55*3)
Factor the coefficients: 40=5*8, 55=5*11. You're left with
8 / 33.
If you really meant y^3 down below, which you need to make clearer; it's not "3y", then you'd have 8 / (33y^2), because y / y^3 = 1/y^2.
2006-10-01 16:11:56 · answer #2 · answered by James L 5 · 1⤊ 0⤋
The x^2 cancel out leaving you with 40y/55*3y. Then, you simplify to 40/165
2006-10-01 16:11:31 · answer #3 · answered by MateoFalcone 4 · 0⤊ 0⤋
8/33
2006-10-01 16:38:08 · answer #4 · answered by The Ideal Son 1 · 0⤊ 0⤋
40x^2y/[55x^2(3y)]
The x^2 and the y cancel, giving
40/165
which can be further simplified to
8/33
Note: Using the character ^ and the brackets [](), you should learn how to state algebraic expressions in thes medium.
2006-10-01 16:21:55 · answer #5 · answered by kindricko 7 · 1⤊ 0⤋
Jeepers, you've got all the data! Just break it down LIKE YOUR WORKBOOK TELLS YOU TO DO!
(40 times 40)/(55x55) and you know the rest
2006-10-01 16:11:59 · answer #6 · answered by Anonymous · 0⤊ 1⤋