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x2ndpower-36/x2nd power+6x=

2006-10-01 09:06:46 · 4 answers · asked by lovinmymatt 2 in Science & Mathematics Mathematics

4 answers

You have (x^2-36) / (x^2+6x).

The numerator is a difference of two squares, so it factors into (x+6)(x-6).

The denominator can be factored into x(x+6).

Cancel the (x+6)'s above and below. You're left with (x-6)/x, which can also be written as 1-6/x.

2006-10-01 09:10:00 · answer #1 · answered by James L 5 · 0 0

You can state the expression as follows:

(x^2 - 36)/(x^2 + 6x)

The numerator can be referred to as the difference of two squares, and can be factored into (x + 6)(x - 6)

The denominator can be factored into x(x + 6)

So the expression can now be written as

[(x + 6)(x - 6)]/[x(x + 6)]

And (x + 6) can be removed from both the numerator and denominator

(x - 6)/x

is the simplest form

2006-10-01 16:15:32 · answer #2 · answered by kindricko 7 · 0 0

x^2 - 36 / x^2 + 6x
= (x-6)(x+6) / (x)(x+6)
= (x-6)/x
or 1 - 6/x

2006-10-01 16:10:39 · answer #3 · answered by kb27787 2 · 0 0

lets say ur problem is 4/8 all you have to do is divide both by something that goes into them. the easiest way to do this is by 2 for evens or 3 by odds. somewhat>!?

2006-10-01 16:10:44 · answer #4 · answered by avatarmaunie 1 · 0 0

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