3y+z=am-4y solve for y
km+5x=6y solve for m
2006-10-01 07:29:33 · 8 answers · asked by Anonymous in Education & Reference ➔ Homework Help
3y+z=am-4y; first you want to isolate the variable you want-y-so you subtract z from both sides to get 3y=am-4y-z, then you add 4y from both sides to get 7y=am-z, then you divide by 7 to get y=(am-z)/7
km+5x=6y; again, you want to isolate the variable, so you subtract 5x from both sides to get km=6y-5x, then to get m by itself, you divide both sides by k, to get m=(6y-5x)/k
Hope that helps :)
2006-10-01 07:37:08 · answer #1 · answered by Anonymous · 0⤊ 0⤋
3y + z = am - 4y
3y + 4y= am +z
7y = am+z
y=(am + z) / 7
explanation:
add 4y to both sides of the equation, so in the left part now we have 3y + 4y + z and in the right only am because -4y +4y =0
now we add z to both sides of the equation, we do this because we want to keep all the y s in the left and the rest in the right
after adding z to both sides we have 3y + 4y= am +z
3y + 4y is 7y so now we have 7y = am+z
to have only y on the left side we divide both sides with 7 ( because 7y / 7 = y)
so we'll have y=(am + z) / 7
the second is more simple:
substract 5x from both sides:
km= 6y -5x
divide both sides to k
m= (6y - 5x) / k
NOTE: k cannot be 0
2006-10-01 07:50:08 · answer #2 · answered by Deep Thought 5 · 0⤊ 0⤋
The first step in any algebra problem is to isolate the variable. So if you're solving for y, you want to bring the rest to the other side.
3y+z=am-4y 3y=am-4y-z 3y+4y=am-z 7y=am-z
y=(am-z)/7
km+5x=6y km=6y-5x m=(6y-5x)/k
2006-10-01 07:38:33 · answer #3 · answered by Rex 4 · 0⤊ 0⤋
3y+z=am-4y subtract am from both sides
3y+z-am=-4y subtract 3y from both sides
z-am= -7y divide both sides by -7
(z-am)/-7=y
km+5x=6y subtract 5x from both sides
km=6y-5x divide both sides by k
m=(6y-5x)/k
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2006-10-01 07:40:17 · answer #4 · answered by Anonymous · 0⤊ 0⤋
With these types of math problems you combine like terms (like in the first problem the 3y and 4y after you decide which side is the better side to do so, depending on what you are solving for. Your goal is to isolate your y on one side because that is the one you are solving for in the first problem. In the second one, isolate the m which is part of km on one side by itself. In this problem you will divide by k on both sides to get your final product. Others have included answers, I hope this explanation helps you somehow.
2006-10-01 07:56:12 · answer #5 · answered by Goldenrain 6 · 0⤊ 0⤋
An algebra problem: First one: Combine expressions containing y on one side of equal sign, then solve for y.
3y+4y=am-z
7y=am-z Therefore, y=am-z/7
Second Problem: m=(6y-5x)/k. The skills needed to solve these problems are: understanding what an equation is; knowing that what one does to one side of the equal sign must be done to the other side; knowing how to factor; and knowing your rules of signs. Lastly note the use of parenthesis in problem 2.
2006-10-01 07:41:22 · answer #6 · answered by CfrancS@sbcglobal.net 1 · 0⤊ 1⤋
3y+z=am-4y
Add 4y to both sides
7y+z=am
Subtract z from both sides
7y=am-z
Divide both sides by 7
y=am-z/7
km+5x=6y
Subtact 5x from both sides
Km=6y+5x
Divide both sides by k
m=6y+5x/m
2006-10-01 07:42:57 · answer #7 · answered by D192 2 · 0⤊ 1⤋
in first question its "y" you have to make separate from other terms and coefficients, similarly "m" in second question.
3y+z=am-4y
3y+4y=am-z
7y=(am-z)
y=(am-z)/7
km+5x=6y
km=6y-5x
m=(6y-5x)/k
if you use digital pen(pen tablet) to write and audio toi listen then i can make explanation more clear.
2006-10-01 07:37:20 · answer #8 · answered by flori 4 · 0⤊ 0⤋