How to find "smallerst positive interger that when multiplied with 56 makes a perfect square.
2006-10-01 06:43:40 · 8 answers · asked by Jenny 2 in Science & Mathematics ➔ Mathematics
Factor 56 into prime numbers
56 = 2 * 28 = 2 * 2 * 14 = 2 * 2 * 2 * 7
Factor out perfect squares already present (2 * 2 = 4)
Left with 2 *7 or 14.
Answer is 14.
2006-10-01 06:48:52 · answer #1 · answered by gerardw 2 · 0⤊ 0⤋
prime factors of 56 are 2, 2, 2, 7
since 2 is occuring thrice and 7 once the no is not a perfect square
to make it a perfect square we have to multiply it by 2 and 7 so that every prime factor of the no. occurs twice
to make a perfect square we hav to multiply 56 by 14(2*7)
2006-10-01 13:59:09 · answer #2 · answered by Cool guy 2 · 0⤊ 0⤋
14
2006-10-01 17:03:58 · answer #3 · answered by superstar 2 · 0⤊ 0⤋
My guess is since 56 = 7 * 2 * 2 * 2 you would need another 7 and a 2 so it's 14.
2006-10-01 13:48:54 · answer #4 · answered by Barkley Hound 7 · 1⤊ 0⤋
56 * 14 = 784
784 is a perfect square.
28 x 28 = 784
So the answer is 14.
2006-10-01 13:46:42 · answer #5 · answered by serpagon 3 · 1⤊ 0⤋
see if 56 * 14 = 784
sqrt of 784 is 28
2006-10-01 14:00:06 · answer #6 · answered by newyork123 2 · 0⤊ 0⤋
56k=n^2
2^3 *7 * k=n^2
Multiplying by 2 and 7 does the trick.
We now have
2^4 * 7^2 = (2*7)^2 = 14^2 = 196.
The answer is 2*7 = 14
2006-10-01 14:01:29 · answer #7 · answered by bluecloud23 2 · 0⤊ 0⤋
simple the answer is 14.believe us
2006-10-01 13:54:27 · answer #8 · answered by Val 2 · 0⤊ 0⤋