One serving of canned beets contains 1 gram of protein and 6 grams of carbohydrates. One serving of canned red beans contains 6 grams of protein and 20 grams of carbohydrates. How many servings of each would it take to get exactly 21 grams of protein and 78 grams of carbohydrates?
beets = t
beans = n
1t + 6n = 21 t = 21 – 6n
6t + 20n = 78 6(21-6n) + 20n = 78
126 – 36n + 20n = 78
48 = 16n
n = 3
t = 21 – 6(3) = 3 3 beets and 3 beans
2006-10-01 06:21:43 · 4 answers · asked by SCHNITZEL 1 in Science & Mathematics ➔ Mathematics
This is perfect! Great job. :)
2006-10-01 06:40:00 · answer #1 · answered by SmileyGirl 4 · 0⤊ 0⤋
I would probably break it up into 2 equations first
t+6n=21 or t=21-6n,
and
6t+20n=78
substitute t
6(21-6n) + 20n = 78
solve for n
126 - 36n + 20n = 78
-16n = -48 or n = -48/-16
n = 3...then solve for t using either of the first equations
2006-10-01 06:43:30 · answer #2 · answered by Anonymous · 0⤊ 0⤋
these steps are perfect
2006-10-01 07:03:53 · answer #3 · answered by newyork123 2 · 0⤊ 0⤋
looks ok
2006-10-01 09:30:53 · answer #4 · answered by KYP 1 · 0⤊ 0⤋