2006-10-01 06:07:18 · 7 answers · asked by ram2003 1 in Science & Mathematics ➔ Physics
32 cells at 3 v each would total (32 * 3) 96 V, but you have 84 V, so a deficit of 12. Each reversed cell drops the expected potential by 6 Volt (subtracting 3 V instead of adding 3 V), so 2 cells are reversed.
2006-10-01 06:13:43 · answer #1 · answered by Vincent G 7 · 1⤊ 0⤋
2
2006-10-01 13:09:38 · answer #2 · answered by danthemanbrunner 2 · 1⤊ 0⤋
There are 84/3 = 28 cells which contribute to the emf
That means that 2 cells are reversed.
These 2 cells cancel the contribution of 2 other cells, leaving 28 cells to contribute to the emf
2006-10-01 13:12:07 · answer #3 · answered by mitch_online_nl 3 · 0⤊ 0⤋
definitely 2.
Actual value of voltage it is supposed show when all the batteries are connected in series is,
32 x 3 = 96
Every battery of 3 produces negative 6 volts when connected in reverse.
that is, Calculated Value minus Apparent Value shown = 12 V
and 96 -12 = 84.
that proves, 2 Batteries are connected in reverse.
2006-10-01 13:57:44 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Right..Kirchoff's law..summation of the voltage in a loop.
96-84v =12v ..
12/6=2
2006-10-01 13:16:34 · answer #5 · answered by ironbrew 5 · 0⤊ 0⤋
Two but I'd love to know why you are asking the question, Have you actually done this?
I suppose it could be four cells that have short circuited.
2006-10-01 17:18:01 · answer #6 · answered by bo nidle 4 · 0⤊ 0⤋
FIVE
2006-10-01 14:16:07 · answer #7 · answered by Infinity 7 · 0⤊ 0⤋