2006-10-01 03:06:19 · 10 answers · asked by Muge E 2 in Science & Mathematics ➔ Physics
Twice a day due to solar tides. However these would be of much smaller amplitude about three to four times smaller than now.
2006-10-05 14:46:07 · answer #1 · answered by bluecloud23 2 · 1⤊ 0⤋
no there will be no tides because the moon motives tides because searching on how far the gap the moon is to the earth the gravity from the moon impacts the oceans tides so devoid of the moon i guess the tides does no longer be extreme or low they'd be impartial tide
2016-11-25 20:22:27 · answer #2 · answered by Erika 4 · 0⤊ 0⤋
Tides are cause by the pull of gravity from extraterrestrial bodies on large bodies of water (actually on all water, even small bodies, but the effects are more pronounced on large bodies). Without the Moon, life as we know it would not exist on Earth; but the Sun would continue to tug at the Earth, causing tidal action.
However, the tug from the Sun is less than the tug from the Moon; so the ebb and flow of ocean tides would be significantly less than with the Moon still around. Check this out:
3 Suppose you weigh 100 pounds here on Earth. Would you like to know what you would weigh in different locations in space? Just look at this list.
Earth - 100 lbs
Moon - 17 lbs
Mercury - 38 lbs
Jupiter - 236 lbs
Pluto - 7 lbs
the sun - 2407 lbs
a white dwarf - 130,000,000 lbs
a neutron star - 14,000,000,000,000 lbs
in a spaceship far out in space - 0 lbs [See source.]
As you can see, the Sun's tug on its surface is about 2400/17 times the tug of gravity on the Moons surface. At the respective surfaces, the Sun's gravitational pull is about 140 times stronger than the Moon's. So why would the Sun's pull on Earth's oceans be less than the Moon's tug?
Because the Sun is 93 million miles away from Earth and the Moon is only roughly .23 million miles away. The pull of gravity diminishes as the inverse square of the distance between two bodies. F = GmM/r^2 is the equation for the force of gravity between two bodies like Earth (m) and the Sun (M) at a distance r between them. f = 17 pounds on the Moon and F = 2400 pounds on the Sun. But these are on the respective surfaces.
f' = 17/(.23^2) = 321, which is the Moon's tug on Earth some 230,000 miles away; and F' = 2400/(93^2) = .28 is the Sun's pull on Earth some 93 million miles away. Thus, you can see the Moon's tug is some 321/.28 = 1146 times more effective than the Sun's effect on Earth.
2006-10-01 05:00:20 · answer #3 · answered by oldprof 7 · 0⤊ 1⤋
The Earth would not have tides because the gravitational pull from the moon is the cause of it. You would not get one (aside from very very small ones) from the sun because the whole mass of the earth and water is in an orbit around the sun. The gravitational effect from other planets, which would have an effect on the tides, is too low.
2006-10-01 03:09:51 · answer #4 · answered by polloloco.rb67 4 · 0⤊ 2⤋
everyday due to sun. The suns tide is smaller than moons tide.
2006-10-01 05:18:57 · answer #5 · answered by Dr M 5 · 1⤊ 0⤋
There are solar tides, but they are insignificant compared to lunar tides.
2006-10-01 03:09:27 · answer #6 · answered by nowallp 1 · 0⤊ 0⤋
The earth would have tides, but very small ones, where it really would be negligable.
2006-10-01 04:15:13 · answer #7 · answered by trancevanbuuren 3 · 0⤊ 2⤋
I would think that without the moon we wouldn't realky have high and low tides.
2006-10-01 03:11:30 · answer #8 · answered by David B 2 · 0⤊ 2⤋
None! Without the moon, we wouldn't be having this conversation!
2006-10-01 11:08:22 · answer #9 · answered by Anonymous · 0⤊ 1⤋
well we not have lunar tide, instead we will have solar tides.
2006-10-01 04:00:27 · answer #10 · answered by I am rock 4 · 1⤊ 0⤋