first of all, a squared x squared is exactly the same as ax squared, becuase a*a*x*x (a squared x squared) is just rearranging a*x*a*x (ax squared), and the order of multiplication doesn't matter.
second, (ax+b)(ax+b) is ax squared PLUS 2 times axb PLUS b squared. or: a*x*a*x + 2*a*x*b + b*b
2006-10-01 00:49:17
·
answer #1
·
answered by No Mo 2
·
1⤊
0⤋
(ax + b)(ax + b) = (a^2)(x^2) + 2abx + b^2.
The first term is "a squared x squared," which can also be written (ax)^2, or "ax squared." They're the same, except that "ax squared" could be confused with a(x^2), or "a x squared," where a is not squared, so we normally say "a squared x squared." You could say "the quantity ax, quantity sqared," if you wanted. When you raise a product to an exponent, you have to raise every factor to that power.
2006-10-01 07:49:51
·
answer #2
·
answered by DavidK93 7
·
1⤊
0⤋
In many problems it is of more interest as to whether you are dealing with x, x squared or x cubed, etc. than the value(s) of the particular constants. Lines (linear), squares and cubes (in equations) are very different animals. The constants (a and b, etc.) affect how large the animal is not how to deal with it. Hope that helps a little.
2006-10-01 08:47:27
·
answer #3
·
answered by Kes 7
·
0⤊
0⤋
(ax+b)(ax+b)=axax +axb + bax + bb
=aaxx +2axb +bb
=a^2x^2 +2axb +b^2
a squared x squared + 2axb + b squared
hopefully by expanding this to see what happens helps?
2006-10-01 07:50:20
·
answer #4
·
answered by Drew T 1
·
2⤊
0⤋
(ax+b)(ax+b)
=(ax+b)^2
=a^2x^2+2abx+b^2 or
=(ax)^2+2abx+b^2
You can write it either way
It is just the same
2006-10-01 07:51:29
·
answer #5
·
answered by openpsychy 6
·
0⤊
0⤋
lets say
ax*ax -----------------------------------> (ax)squard = a squard * x squard
+
ax*b -------------------------------------> abx
+
b*ax----------------------------------------> abx
+
b*b------------------------------------------> b squard
2006-10-01 08:03:49
·
answer #6
·
answered by SoMe OnE 1
·
0⤊
0⤋