2006-10-01 00:26:46 · 3 answers · asked by purp 1 in Science & Mathematics ➔ Physics
It will intially act as a short circuit, but as it fills it will provide greater impedance until it finally acts as an open circuit and current ceases to flow. If there is just a capacitor, it will charge almost instantaneously. If it is an RC circuit, containing a resistor and a capacitor, with a voltage of V, the voltage across the capacitor will be V(1-e^(-t/RC)) and current will be (V/R)*e^(-t/RC), an exponential decay. RC is normally referred to as τ, the time constant, and the circuit is generally said to have run its course after 5τ.
2006-10-01 00:33:14 · answer #1 · answered by DavidK93 7 · 0⤊ 0⤋
Capacitor in a DC circuit is the same as open circuit. It will charge the capacitor.
2006-10-01 08:06:17 · answer #2 · answered by openpsychy 6 · 0⤊ 0⤋
It will appear as a short circuit (uncharged cap) at first then charge like a battery until it reaches the level of the source, provided the source is not higher than the cap can handle. when the source is removed, it will slowly discharge this rate is dependent on the capacity of the cap.
2006-10-01 07:37:11 · answer #3 · answered by treb67 2 · 0⤊ 0⤋