a solution of potassium chromate is mixed with a solution of lead nitrate in a test tube. a precipitate forms in the test tube.
i. write a word equation for the above reaction.
ii. write a balanced equation for the overall reaction showing states.
2006-10-01 00:16:10 · 3 answers · asked by Anonymous in Education & Reference ➔ Homework Help
Pb(NO3)2 + K2CrO4 --> PbCrO4 + 2KNO3
Lead(II) nitrate plus Potassium chromate yield Lead chromate and 2 moles of Potassium nitrate.
2006-10-01 00:26:54 · answer #1 · answered by S A 3 · 0⤊ 0⤋
I hope this helps. Good luck.
Adding yellow potassium chromate to colorless lead(II) nitrate produces a yellow precipitate.
Solution A: 0.2 M potassium chromate (yellow)
Solution B: 0.2 M lead(II) nitrate (colorless)
Precipitate: (yellow)
Pb(NO3)2(aq) + K2CrO4(aq) --> PbCrO4(s) + 2 KNO3(aq)
2006-10-01 00:24:30 · answer #2 · answered by JZ 5 · 0⤊ 1⤋
JZ's equation is correct.
the word equation would be:
potassium chromate + lead (II) nitrate = potassium nitrate + lead (II) chromate
2006-10-01 16:44:40 · answer #3 · answered by loki 2 · 1⤊ 0⤋