i want the procedure for testing % KMnO4. but the simple procedure of testing only, by titration.?

Question

please give the titration procedure and how to calculate. tnx

Answer 1

Net ionic equation for a re-dox reaction:
(MnO4)-1 + 5 Fe+2 + 8H+ --> Mn+2 + 5 Fe+3 + 4 H2O
or
2(MnO4)-1 + 5 (C2O4)-2 + 16H+ --> 10CO2 + 2Mn+2 + 8H2O

The second (reaction with oxalate) might be easier.

If you use Sodium oxalate, dry the sample at 105 degrees C for about one hour to get rid of any water. Measure 0.05 moles of the dried powder:

0.05 moles * 134.00 g/mole = 6.7000 grams of Sodium oxalate.

Titrate with your unknown Potassium permanganate solution. Record the volume at which the solution just turned pinkish.

Since one mole of permanganate reacts with 5 moles of oxalate the volume of permanganate will contain 0.01 moles.

MW = 158.0 g/mole * 0.01 moles = 1.580 grams of KMnO4

1.580 g / volume used to titrate * 100 = % KMnO4

Answer 2

See the links. You must be able to understand redox reactions. The oxalate method is the most common.