factoring for 2 binomials with like terms?

Question

1)2x^2+5x+2=
2)7x^2 -15x+2=
3)2x^2-7x+3=
4)7x^2-10x-8=

Answer 1

1= (2x +2) (x+1)
2= (7x -1) (x-2)
3= (2x -1)(x-3)
4= (7x +4) (x-2)

These are your answers they are right I have AP Calculus

Answer 2

First you multiply the first number by the last number. So for the first problem multiply 2x2=4. Then you find two numbers that multiply to be that number, and add to be the middle number. The only numbers that work are 4 and 1. If you multiply 4x1 you get 4, and if you add 4+1 you get 5. Then you split the middle term so you have an equation with four terms. You will get 2x^2+4x+1x+2. Then you split up the equation, so you have (2x^2+4x)+(1x+2). Then you find the common factor for each binomial. For the first part, factor out a 2x, and for the second part factor out a 1. You get 2x(x+2)+1(x+2). Then you see that you have (x+2) twice. So write it one time in parentheses, and then in another set of parenteses you write what you have left. You will end up with (x+2)(2x+1). For the second problem multiply 7x2=14. So you need two numbers that multiply to be 14 and add to be -15. (-14)x(-1) works. So split the equation into four pieces. You get 7x^2-14x-1x+2 or (7x^I2-14x)+(-1x+2). Factor out 7x from the first part, and -1 from the second. You get 7x(x-2)-1(x-2). Then you end up with (x-2)(7x-1). I will let you do the other problems by yourself.

Answer 3

1. (x+2)(2x+1)
2. (7x-1)(x-2)
3. (2x-1)(x-3)
4. (7x+4)(x-2)

just to let u know the 1st answer on the 1st post is wrong by the person in AP calc.

Answer 4

1. (2x+1)(x+2)
2. (x-2)(7x-1)
3. (2x-1)(x-3)
4. (7x+4)(x-2)
Good Luck !

Answer 5

Ok. We should be showing you how to arrive at the answers instead of just giving them to you directly. so far not one of you dudes has done that.

1. (2x+1)(x+2)