How to calculate potential diffeence of a three parallel connected resistors?

Question

suppose A is starting point.Three resistors are connected in parallel.
R=r1=r2=r3=1,and E1=3volt,E2=2volt,E3=1 volt.
suppose a point A is starting point and after that R is resistor,from resistor,three parallel resisters are connected say r1=r2=r3=1,and E1=3 volt,E2=2 volt and E3=1 volt. outside the circuit point B is the end.What will be the potential difference between point A&B

Answer 1

If the resistors are connected in parallel, the potential difference across all three must be the same. Only if they are connected in series can the voltage across each one be different.

Answer 2

It is a wrong question my dear coz pot. diff across parallel resistance is always same.
U can try this , add the reciprocal of given resistance i.e
1/R = 1/r1 + 1/r2 + 1/r3
and current must be given 2 u
so now apply formula V=IR i.e Ohm's law

Answer 3

think one has resistance R and potential large difference is V; at the same time as resistors are linked in sequence the consequent resistance is 3R, hence potential dissipation p1=V^2/(3R) at the same time as resistors are linked in parallel the consequent resistance is R/3 p2=V^2/(R/3)=9(V^2/3R)=9p1 yet, p1=27 W, so p2=9*27=243 W

Answer 4

If r1, r2 and r3 are same how can E1, E2 and E3 are different ?????

Answer 5

potential differance across parallel resistors is always the same, only current varies

Answer 6

The PD remains same across a parrallel resistor .
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Answer 7

Impossible question! Did you wrongly ask parallel and series?

Answer 8

use a potentenceometer