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how would you calculate the mass of potassium hydrogen phthalate needed to neutralize 10mL of an ~0.1NaOH solution?

2006-09-30 16:33:56 · 2 answers · asked by uscgurrl21 1 in Science & Mathematics Chemistry

2 answers

KHC8H4O4 + NaOH

Since molarity= mole/ volume,

mole = molarity X volume
mole = (0.1)(0.01)=.001 mole (with a 1:1 mole ratio, KHC8H4O4 has the same mole, .001)

Molar mass = mass/ mole
mass = mole X molar mass (of KHC8H4O4)

mass = (.001 mole)(204.22mole/g)
mass of KHC8H4O4 required = .204 g

2006-09-30 17:21:52 · answer #1 · answered by Jacqueline 2 · 0 0

Determine the number of moles of NaOH you have (hint: it's 1 mmol), then determine how many moles of KHP you'll need to neutralize it (hint: it's also 1 mmol), then use the molecular weight of KHP (no, I don't know what it is off the top of my head) to get the mass.

2006-09-30 16:43:10 · answer #2 · answered by TheOnlyBeldin 7 · 0 0

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