9.81 m/s^2 is the gravitational accelleration of the earth. the rate at which objects fall due to the gravity on earth. in contrast, the moon's gravitational acceleration is approx. 1.66 m/s^2
2006-09-30 16:33:09
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answer #1
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answered by mcdonaldcj 6
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The acceleration of gravity is 9.8 m/s2. An object just above the surface of the Earth will fall at that rate of acceleration.
2006-09-30 16:33:38
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answer #2
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answered by Anonymous
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It means that the force exerted by the Earth's gravity on any unsupported object near the surface of the Earth results in an acceleration of 9.8 m/s/s
2006-09-30 16:40:21
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answer #3
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answered by Helmut 7
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9.8 m /s2 is the value of acceleration due to gravity. It means when a body is falling down or going up, its change in velocity(acceleration or retardation) will increase or decrease respectively, by 9.8 m / s2.
2006-09-30 18:31:40
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answer #4
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answered by Anonymous
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g the acceleration due to Gravity commonly assigned the value 9.81 m/s^2, can be explained as follows,
Starting with F = ma, or in the case of a falling object, F = mg (neglecting drag due to air friction)
g = F/m
F in this case is the force exerted by the Earth's Gravitational field, and is given by,
F = GMm / r^2
G = Gravitational constant
M = mass of Earth
m = mas of object on Earth.
or
g = F/m = GM / r^2
g = 9.81 m/s^2 is actually associated with Sea-level assuming a perfectly spherical, uniformly dense, Earth. As you move around on the Earth, slight variations in F due to altitude, the non-spherical shape of the Earth, and density variations cause slight variations in g.
But this is what g = 9.81 m/s^2 means.
2006-09-30 16:38:58
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answer #5
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answered by entropy 3
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It means that in the absence of air resistance, things in freefall speed up 9.8 meters per second for every second that they fall. So, for example, if you drop a coin off a building and ignore air resistance, it would be going 9.8 m/s after the first second, 19.6 m/s after the 2nd second, 29.4 after the 3rd, etc...
It also means that if you want to find the weight of an object on earth (in Newtons), you would mulitply the mass of the object (in kg) by 9.8 m/s^2.
Hope this helps! :)
2006-09-30 16:34:47
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answer #6
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answered by cushdogjr 3
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WOW, thanks so much for this question.
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One of my images demonstrates the 69/light/dark and it has many meanings, but the image also holds what Cory wrote: '''9.81 m/s^2 is the gravitational accelleration of the earth. the rate at which objects fall due to the gravity on earth. '''
My blog also showed the 1836 from the electron.
As a self educated person I have to wait for others to show something that then I discover holds relevance to science etc...
My work is the creation of my dreams....
Thanks for posting this I shall now highlight it in my 360
2006-09-30 23:42:50
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answer #7
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answered by WW 5
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in accordance to the respond given via the 1st guy or woman, it may be the region it is closest to the Earth's middle. i think which would be loss of life Valley out west. i became into going to declare Mariana's Trench, yet it is underwater. additionally, as others have stated, the version interior the stress between thses aspects is so small that it is insignificant.
2016-12-26 06:11:34
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answer #8
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answered by Anonymous
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When u drop an object toward the ground, it will fall down at a rate of 9.8m/s2
2006-09-30 19:46:04
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answer #9
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answered by Anonymous
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it's the acceleration of all falling objects on earth, disregarding friction (from the air)
2006-09-30 16:37:23
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answer #10
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answered by Jeffrey W 3
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