A spaceship lifts off vertically from the Moon, where the freefall acceleration is 1.6m/s^2. If the spaceship has an upward acceleration of 1.0 m/s^2, as it lifts off, what is the magnitude of the force on the spaceship and its pilot, who weighs 735 N on Earth?
2006-09-30 16:17:15 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Physics
Explain please how you get this answer
2006-09-30 16:27:49 · update #1
Use Newton's 2nd law, F=ma, to solve this problem.
First, determine the mass of the spaceship and pilot as follows:
735N = m * 9.8 m/s^2
Next, to find the magnitude of the net force on the spaceship and its pilot, plug your value for m into the equation F=ma (remember that a=1.0 m/s^2)
Solve the equation, and you will have the answer you are looking for. Good luck! :)
P.S.
The 1.6 m/s^2 is extra info that is not needed, and the 9.8 m/s^2 is the freefall acceleration on earth...
2006-09-30 16:29:30 · answer #1 · answered by cushdogjr 3 · 0⤊ 0⤋
Gravity is the collective stress of all of the mass in a physique. each and each grain of sand and molecule of water contributes to Earth's gravity. you may no longer replace the gravitational container of Earth to any extent further than you may walk to the moon, you may no longer make a ten lb barbell magically weigh 4 lbs.
2016-12-26 06:10:50 · answer #2 · answered by Anonymous · 0⤊ 0⤋
F = 735(1+1.6)/9.8
2006-09-30 16:30:50 · answer #3 · answered by Helmut 7 · 0⤊ 1⤋