The left cable is horizontal. The right hand cable is attached at a 40 degree angle. For example if it were in a doorframe, the left cable would be attached to the side of the doorframe, and the right cable would be attached to the top of the door frame at a 40 degree angle, with the weight hanging where they meet.
What is the tension in the cable slanted at a 40 degree angle? Answer in N
What is the tension in the horizontal cable? Answer in N
2006-09-30 13:11:24 · 2 answers · asked by Dee 4 in Science & Mathematics ➔ Physics
I take it you mean a 40 degree angle to the horizontal. Then the vertical component of the tension in the slanted cable must be 59N; this is the only force holding the weight up. Then the total tension in the slanting cable must be 59/sin 40=91.79N and the horizontal component of the tension in the slanting cable must be 91.79 cos 40=70.32N. This must be balanced by the tension in the horizontal cable which must be 70.32N.
2006-09-30 13:32:18 · answer #1 · answered by zee_prime 6 · 0⤊ 0⤋
This couldn't occur as the weight would soide to the left. However if there were a stop on the cable preventing this slide the tension in the right hand cable is 59/Sin 40 = 91.79N. This assumes that the 40 deg is to the horizontal. The reason for this is that the horixontal side of the cable cannot offer any vertical resistance to support the weight.
2006-09-30 13:32:34 · answer #2 · answered by Man_of_Aran 2 · 0⤊ 0⤋