I assume you mean "superscript", not "subscript". Then the question is, what is the largest x such that 2^x (2 to the power x) divides 10! (not "divides by").
To answer this, look at the prime factorization of each of the numbers 1 through 10. Only the even numbers are divisible by 2, so we restrict ourselves to those. You have 2, then 4 = 2*2, then 6 = 2*3, 8=2*2*2, and 10=2*5. There are 8 factors of 2 altogether, so x=8. 10! is divisible by 2^8 = 256.
2006-09-30 11:40:42
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answer #1
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answered by James L 5
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I think you mean the largest x such that 2^x divides 10!
Count all the different exponents of 2 in the product and add them.
10 1
8 3
6 1
4 2
2 1
Total: 8
So 2^8||10!
2006-09-30 11:15:34
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answer #2
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answered by steiner1745 7
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The factors of 2^x are all powers of 2, therefore there are no 2^x numbers that divide 10!.
2006-09-30 11:04:43
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answer #3
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answered by Anonymous
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2016-12-15 17:30:37
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answer #4
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answered by ? 3
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Let 2^x/10!= 1
Taking log both sides
x log 2 = log 10!
x = log10!/log 2=21.79106119
Therefore x =21.79106119
2006-09-30 13:00:33
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answer #5
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answered by Amar Soni 7
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the questions is not clear
2006-09-30 10:59:59
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answer #6
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answered by raj 7
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having problems with your homework...?
2006-09-30 11:04:41
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answer #7
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answered by HoTbOd sWiMmeR 2
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