even if you do not have an answer to this question I would appreciate if you told me how to go about doing it...thanks
2006-09-30 10:37:49 · 7 answers · asked by clara 1 in Science & Mathematics ➔ Mathematics
In total there 20 + 16 = 36 games
A 50% winning record is obtained by half of 36 games, which is 18 games. T has already won 9 games, so he has 9 more games to win in order to reach the desired 18 games (50% of 36).
2006-09-30 10:45:34 · answer #1 · answered by daniel_cohadier 3 · 1⤊ 0⤋
So if a total of a 36 games are to be played, 18 must be won in order to have a 50% winning record; since 9 have been one in the first 20, 9 more must be one in the last 16.
2006-09-30 18:33:04 · answer #2 · answered by bruinfan 7 · 1⤊ 0⤋
T has played 20 games, and there are 16 left, so there are 36 games total.
To have a 50% winning record, T must win 50% of 36 of those games, which is equal to 18 games.
T has already won 9 games, so 18-9=9 more wins are needed.
2006-09-30 17:46:03 · answer #3 · answered by James L 5 · 1⤊ 0⤋
9
2006-09-30 18:46:20 · answer #4 · answered by Chippie 2 · 0⤊ 0⤋
20 + 16 = 36 total games
36/2 = 18
T needs to win 18 games.
T already won 9, so T needs to win 18 - 9 = 9 more
2006-09-30 17:45:52 · answer #5 · answered by MsMath 7 · 0⤊ 0⤋
For T to win 50% of total games he/she must win 0.5*(20+16) games = 18 games
so another 9 wins is required
2006-09-30 17:44:44 · answer #6 · answered by ? 7 · 1⤊ 0⤋
(9+x)/36=50/100
x+9=18
x=9
you have to win 9 of the remaining 16 gms
2006-09-30 17:43:57 · answer #7 · answered by raj 7 · 1⤊ 0⤋