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Calculus... I'm following the steps that would take to get the answer to this problem, but I think my math might be wrong somewhere along the line. If you think you could help me work this problem out, that would be great!

2006-09-30 08:56:09 · 1 answers · asked by Anonymous in Education & Reference Homework Help

1 answers

f'(x)=-6x/(3x^2+4)^2
f"(x)=6(9x^2-4)/(3x^2+4)^3
f"(x)=0
==>
x=2/3
or
x=-2/3
so
x=2/3

2006-09-30 22:22:33 · answer #1 · answered by Mamad 3 · 0 0

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