HCl is a strong acid so it dissociates 100%. For every mole of HCl, 2 moles of ions will be formed. No Ka can be calculated since there is no HCl left and Ka=[H+][Cl-]/[HCl] and we can't divide by zero
2006-09-30 06:57:07
·
answer #1
·
answered by Greg G 5
·
1⤊
0⤋
Hydrogen chloride (HCl) is a monoprotic acid, which means it can dissociate (i.e., ionize) only once to give up one H+ ion (a single proton). In aqueous hydrochloric acid, the H+ joins a water molecule to form a hydronium ion, H3O+:
HCl + H2O â H3O+ + Clâ
Molecular model of hydrogen chloride.The other ion formed is Clâ, the chloride ion. Hydrochloric acid can therefore be used to prepare salts called chlorides, such as sodium chloride. Hydrochloric acid is a strong acid, since it is practically fully dissociated in water.
Monoprotic acids have one acid dissociation constant, Ka, which indicates the level of dissociation in water. For a strong acid like HCl, the Ka is large. Theoretical attempts to assign a Ka to HCl have been made.[2] When chloride salts such as NaCl are added to aqueous HCl they have practically no effect on pH, indicating that Clâ is an exceedingly weak conjugate base and that HCl is fully dissociated in aqueous solution. For intermediate to strong solutions of hydrochloric acid, the assumption that H+ molarity (a unit of concentration) equals HCl molarity is excellent, agreeing to four significant digits.
2006-09-30 14:27:21
·
answer #2
·
answered by Anonymous
·
0⤊
0⤋