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2006-09-30 06:54:35 · 3 answers · asked by Anonymous in Science & Mathematics Chemistry

3 answers

HCl is a strong acid so it dissociates 100%. For every mole of HCl, 2 moles of ions will be formed. No Ka can be calculated since there is no HCl left and Ka=[H+][Cl-]/[HCl] and we can't divide by zero

2006-09-30 06:57:07 · answer #1 · answered by Greg G 5 · 1 0

Hydrogen chloride (HCl) is a monoprotic acid, which means it can dissociate (i.e., ionize) only once to give up one H+ ion (a single proton). In aqueous hydrochloric acid, the H+ joins a water molecule to form a hydronium ion, H3O+:

HCl + H2O → H3O+ + Cl−

Molecular model of hydrogen chloride.The other ion formed is Cl−, the chloride ion. Hydrochloric acid can therefore be used to prepare salts called chlorides, such as sodium chloride. Hydrochloric acid is a strong acid, since it is practically fully dissociated in water.

Monoprotic acids have one acid dissociation constant, Ka, which indicates the level of dissociation in water. For a strong acid like HCl, the Ka is large. Theoretical attempts to assign a Ka to HCl have been made.[2] When chloride salts such as NaCl are added to aqueous HCl they have practically no effect on pH, indicating that Cl− is an exceedingly weak conjugate base and that HCl is fully dissociated in aqueous solution. For intermediate to strong solutions of hydrochloric acid, the assumption that H+ molarity (a unit of concentration) equals HCl molarity is excellent, agreeing to four significant digits.

2006-09-30 14:27:21 · answer #2 · answered by Anonymous · 0 0

I have no idea 2 points? maybe 10 who knows these things.

2006-09-30 14:02:13 · answer #3 · answered by Barry G 5 · 0 0

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