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3(w^2-x)+2(x-1)-3(w-1)+w^2=

2006-09-30 06:48:53 · 4 answers · asked by HELPME 1 in Science & Mathematics Mathematics

4 answers

3w^2-3x+2x-2-3w+3+w^2
4w^2-3w-x+1

2006-09-30 06:52:50 · answer #1 · answered by Greg G 5 · 0 0

4w^2-x-3w+1

2006-09-30 14:01:14 · answer #2 · answered by venkatarama s 1 · 0 0

3(w^2-x)+2(x-1)-3(w-1)+w^2
=3w^2-3x+2x-2-3w+3+w^2
=4w^2-3w+1-x

2006-09-30 13:57:54 · answer #3 · answered by jack1234 1 · 0 0

3w^2-3x+2w-2+w^2=4w^2+2w-3x-2

2006-09-30 14:12:58 · answer #4 · answered by yupchagee 7 · 0 0

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