7-2xy^2+4y+2x^2=
2006-09-30 06:28:20 · 4 answers · asked by yowhatsgood727 1 in Science & Mathematics ➔ Mathematics
x=3 and y= -2
2006-09-30 06:37:09 · update #1
You sub in 3 in the place of x and -2 in the place of y, so your new equation would look like this
7-2xy^2+4y+2x^2
= 7 - 2(3)(-2)^2 + 4(-2) + 2(3)^2
The you follow the rules of BEDMAS (Brackets, exponents, division and multiplication *in order of appearance* then addition and subtraction *in order of appearance as well*)
= 7 - 2(3)(-2)^2 + 4(-2) + 2(3)^2
= 7 - 2(3)(4) + 4(-2) + 2(9)
Then multiply the numbers which do
= 7 - 2(3)(4) + 4(-2) + 2(9)
= 7 - 24 - 8 +18
Then add and subtract
= 7 - 24 - 8 +18
= -7
So the answer is -7 =D I hope you understood the process
2006-09-30 06:46:15 · answer #1 · answered by Miss Black 2 · 0⤊ 0⤋
when x=3 and y= -2
7-2xy^2+4y+2x^2
= 7 - 2(3)(-2)^2+4(-2)+2(3)^2
= 7- (24) - 8 + 18
= -7
I hope that helps !!
Best wishes, Jordi
2006-09-30 13:43:11 · answer #2 · answered by Jordi 2 · 1⤊ 0⤋
7-2*3*(-2)^2+4*(-2)+2*3^2=7-24-8+18=-7
2006-09-30 16:20:23 · answer #3 · answered by yupchagee 7 · 0⤊ 0⤋
7-2xy^2+4y+2X^2
=2x(x-y^2)+4y+7
There is no further
simplification possible
2006-09-30 13:34:15 · answer #4 · answered by openpsychy 6 · 0⤊ 0⤋