A 7.23 kg block is on top of a table (frictionless, horizontal surface). The first block is connected by a cord passing over a pulley to another block of mass 4.09 kg which hangs in the air over the right side of the table. The cord is weightless & massless and does not stretch. The pulley has no friction or rotational inertia. The acceleration of gravity is 9.8 m/s^2.
Calculate the acceleration of the first block (in m/s^2). I got .361307 and then recalculated and got -2.71837 m/s & doubt either is correct (sigh loudly).
Calculate the tension in the cord (answer in N).
Can't figure out what I am doing wrong....if I am sure I understand and have the right answers it will help me move on to other problems. Thanks in advance for any help.
2006-09-30 05:57:57 · 3 answers · asked by Dee 4 in Science & Mathematics ➔ Physics
Can anyone confirm the answer(s) so I'm sure it's correct?
2006-09-30 08:01:26 · update #1
Accelerating force=4.09*9.8=40N
Total mass=4.09+7.23=11.32kg
Acceleration for both blocks=40/11.32=3.54m/s^2
Force in cord=7.23*3.54=25.6N
2006-09-30 06:08:06 · answer #1 · answered by Anonymous · 0⤊ 0⤋
If the cord is weightless & massless then is does not exist, therefore there is 0 tension.
The force of gravity is the same on both blocks and unless some other factor is included neither will move.
2006-09-30 06:20:20 · answer #2 · answered by echiasso 3 · 0⤊ 1⤋
Show your reasoning and your work and people will be willing to help you rather than give you the answer.
2006-09-30 11:45:06 · answer #3 · answered by Frank N 7 · 0⤊ 0⤋