how would i go about doing this? X= -8 Y= 4?

Question

im supposed to evaluate.

1.) X/Y

2.) [2x-1]/y

3.) [4x+3y]/x

im really stuck please help.

Answer 1

Graph it. It's the only way to really see what the ratio is. Use a piece (or a little part of) graph paper, and draw the X and Y axes through the center, so that you can go minus on the X. Count off the position of the point of X and Y that is mentioned here; put a dot there. Now draw a line between that and the position of the intersection (i.e., where X=0 and Y=0). That slope goes through all the other values of X and Y that have the same proportions. Extend the line beyond your original dot, and also beyond the center of the graph, because no matter how far you go, points along that line will have the same proportions (the same relationship to one another) that your original position had.

Answer 2

Hey there. These 3 problems are simple substitution problems.
1. -8/4

2. [2*-8-1]/4

3. [4(-8)+3(4)]/-8

Now use the order of operations to solve them.

Hope this helps. Good Luck.

Answer 3

1) First write X/Y then substitute, -8/4, that = -2
2)(2x-1)/y,=(2 *-8-1)/4=(-16-1)/4= -17/4=-4.25
3)(4*-8+3*4)/-8 =(-32+12)/-8=10/-8=-1.25

sorry, but I don't know if this is right

Answer 4

1. -8/4
= -2

2. [2(-8)-1]/4
=(-16-1)/4
= -17/4

3. [4(-8)+3(4)]/ -8
=(-32+12)/ -8
= (-20) / -8
= 2 1/2

Answer 5

I could do these when I started high school math.
-8/4
[(2*-8) -1] then divide all this by 4
[(4*-8) + (3*4)] divide by -8

Answer 6

you would take X (which equals -8)and replace it with -8 everytime you see X and the same with Y (which equals 4)

X/Y= -8 divided by 4

Answer 7

1) (-8)/4=-2
2) (2*(-8)-1)/4=-4.25
3) (4*(-8)+3*4)/(-8)=2.5