75^50 or 50^75
75^50
75^(25 * 2)
(75^25)^2
((25 * 3)^25)^2
(25^25 * 3^25)^2
((5^2)^25)^2 * (3^25)^2
5^(2 * 25 * 2) * 3^(25 * 2)
5^100 * 3^50
50^75
50^(25 * 3)
(50^25)^3
((5^2 * 2)^(25))^3
((5^2)^25 * 2^(25))^3
(5^(2 * 25))^3 * 2^(25 * 3)
5^(2 * 25 * 3) * 2^(75)
5^(150) * 2^(75)
5^100 * 5^50 * 2^75
5^100 * (5 * 2)^50 * 2^25
5^100 * 10^50 * 2^25
since the 2 values have 5^100, you can take that out, so
3^50
5^50 * 2^75
so as you can see, since 75^50 has 3^50 and 5^50 * 2^75 as a difference between them
50^75 is much larger than 75^50
Sorry if it got confusing the way i worked it out.
2006-09-30 05:14:18
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answer #1
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answered by Sherman81 6
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50^75 has a greater value...
The first thing to do is to express both the exponents to a common base.
75^50 = (25 x 3)^50 = (5^2 x 3)^50
50^75 = (25 x 2)^75 = (5^2 x 2)^75
The first one is also equal to 5^100 x 3^50 while the second one is also equal to 5^150 x 2^75.
Note that 5^150 x 2^75 can also be written as 5^100 x 5^50 x 2^75. Since the first one is just equal to 5^100 x 3^50, then the latter expression or 50^75 is greater.
2006-09-30 10:27:40
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answer #2
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answered by pterocarpus_indicus05 2
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50^75= 26469779601696900000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000 OR 2.647E+127
75^50= 5663216564269380000000000000000000000000000000000000000000000000000000000000000000000000000000 OR 5.66322E+93
Thus 50^75 is greater than 75^50.
However do not go by the first response to your question.
Just consider the simplest problem of the type you mention.
What is greater 2^3 or 3^2?
2^3 =8
and
3^2=9
You will see that in this case the base is more weighty than power.
2006-09-30 10:26:35
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answer #3
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answered by curious 4
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Power matters!
if the power is greater the final value would be greater.
hence, 75^50 < 50^75.
2006-09-30 11:14:21
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answer #4
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answered by Christa 2
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I would look at it this way:
75^50 = (50*1.5)^50 =50^50 *1.5^50
50^75 = 50^50 * 50^25
Divide out 50^50 from each, then square root 50 (i.e. 2root5) and set both exponents to 50 i.e.
75^50 = 50^50 * 1.5^50
50^75 = 50^50 * (2root5)^50
Which is bigger 1.5^50 or (2root5)^50? Well, both exponents being the same and both 1.5 and 2root5 being greater than 1, (2root5)^50 is going to be bigger than 1.5^50 because 2root5 (about 4.4721359549995793928183473374626) is bigger than 1.5 .
That's probably far from the simplest way of doing and it's probably not a proof but I think that clearly shows that for these particular numbers, 50^75 is the larger.
HTH
2006-09-30 10:42:32
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answer #5
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answered by spongeworthy_us 6
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Answer is 50^75
because 75 times log50 is greater than 50 times log75
2006-09-30 10:36:58
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answer #6
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answered by small 7
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No matter how big the base number is (For example for 75^50,75 is the base),the power decides how big the number is.From here we can say that 50^75 is bigger although the base is smaller than that of 75^50.
2006-09-30 10:25:40
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answer #7
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answered by Kenneth Koh 5
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