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7 answers

(x+2)/(x+1) = (x+1+1)/(x+1)
= (x+1)/(x+1) + 1/(x+1)
= 1 + 1/(x+1)

2006-09-30 03:13:09 · answer #1 · answered by Scott R 6 · 2 1

(x+2)/(x+1)=
(x+1+1)/(x+1)=
(x+1)/(x+1) +1/(x+1)=
1 +1/(x+1)

2006-09-30 10:42:48 · answer #2 · answered by curious 4 · 0 1

OK, all the other answers have shown you the straigtforward steps on piece of paper.
Now look at it mentally/visually....(x+2)/(x+1) means that x+2 on top almost equal to x+1 at bottom
Top is actually more than bottom by the fraction of
1/(x+1).
Which is why it is equal to 1+1/(x+1) :)

2006-09-30 12:41:57 · answer #3 · answered by TheErrandBoy 2 · 0 1

Taking the left hand side of the problem:

(x+2)/(x+1) = (x+1+1)/(x+1)
= (x+1)/(x+1) + 1/(x+1)
= 1 + 1/(x+1)

we have reached to the right.

I guess that is satisfactory

2006-09-30 10:42:34 · answer #4 · answered by Rahul Ghose 4 · 1 1

1 + (1/(x + 1))
multiply everything by (x + 1)

((x + 1) + 1)/(x + 1)

(x + 1 + 1)/(x + 1)

(x + 2)/(x + 1)

2006-09-30 12:24:17 · answer #5 · answered by Sherman81 6 · 0 1

1 + 1/(x+1)

we have x+1 =LCM

SO, 1(X+1)+1/(x+1)*(X+1)
=((X+1)+1)/(X+1), (AS (X+1)/(X+1)=1)
=(X+1+1)/X+1
=(X+2)/(X+1)

SO, (x+2)/(x+1) equal 1 + 1/(x+1)

2006-09-30 10:20:58 · answer #6 · answered by Anonymous · 1 1

rhs = 1 + 1 / (x+1)
= (x+1) + 1 / (x+1) as lcm = ( x+ 1 )
= (x+2) / (x+1) = rhs
i think this is the simplest.

2006-09-30 11:15:09 · answer #7 · answered by RajaRao 2 · 0 1

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