A 65kg person is in an elevator accelerating upwards at the rate of 2 m/s/s. if the person was standing on a scale in the elevator, what would the scale's reading show?
2006-09-30 02:55:09 · 4 answers · asked by tiger 1 in Science & Mathematics ➔ Physics
the acceleration due to gravity on earth is 9.8 m/s^2. If a person were in an elevator that were accelerating upwards at 2 m/s^2 then the overall acceleration would be 9.8 + 2 = 11 m/s^2. Weight is equal to mass * acceleration, so the scale would read:
65 kg * 11.8 m/s^2 = 767 kg*m/s^2 or 767 Newtons (N). If you are looking for an answer in pounds then you would multiply the value of Newtons by 0.22481 to give 172.43 lb.
2006-09-30 03:07:15 · answer #1 · answered by j 3 · 0⤊ 0⤋
any way u can can not calculate the way j is telling u
as u r working againsty the acceleration due to gravity so the total acceleration can not be found by adding the 2 accelerations
just multliply 9.8 and the mass to get the weight
2006-09-30 12:36:06 · answer #2 · answered by ash007 2 · 0⤊ 0⤋
calculate the mass of the body by dividing the weight by the gravitational acceleration.
and then multiply the mass by the net acceleration which will be g-2 ....that will be the reading on the scale.
2006-09-30 10:02:09 · answer #3 · answered by Chris 2 · 0⤊ 0⤋
what exactli IS ur question?
what kinda scale is it?
2006-09-30 10:06:50 · answer #4 · answered by tonima 4 · 0⤊ 0⤋