Help... I can't understand my assignment...?

Question

add:
1. ) 1011011 and 1101011

2. ) aef1 and 34bc

Answer 1

We have a couple close answers here, but none complete yet:

1) This "appears" to be binary which would yield the answer:

11000110 (unlike other answers here). Try it using microsoft's calculator (view scientific - select binary math).

HOWEVER, in order for the numbers to be taken AS binary, there must be a "bin" notation, and without such, the numbers are always assumed to be decimal:

1011011 + 1101011 = 2112022

2) A few poeple here have suggsted that this is hexidecimal. That answer has been correctly identified as: E3AD

HOWEVER, hexidecimal numerics always use UPPER CASE LETTERS! Not presented as such forces the reader to assume that a,b,c,e & f are NOT hexidecimal notation, but variables. Thus the addition would be:

aef1 + 34bc = aef + 34bc

Answer 2

The first one is binary (2 digits) and the second is the hexadecimal (16 digits) system. We normally use the decimal (10 digits). In binary digits are 0 and 1, so if you compare it to decimal it goes: 0=0, 1=1, 2=10, 3=11, 4=100, etc...
So for this, you start adding them from right to left just like you usually do: 1+1=10, so you write 0 and "remember" 1, then 1+1+1(you "remembered")=11, write 1 and "remember" 1 and so on....
the result is 11000110
The hexadecimal is: 0-9 same as decimal and then a=10,b=11,c=12,d=13,e=14,f=15. So c+1=d,b+f=1a (write a,remember 1), e+4+1=13(write 3,remember 1), a+3+1=e, so its
e3ad.
It's a bit confusing cause we are not used to think in this way, so search the net a bit if you don't quite understand....

Answer 3

My guess is that the first is a binary computation and the second is a hexadecimal one. Addition in each is done just like in base 10 except for some minor changes.

For example, in aef1+34bc, you will put them above each other
aef1
34bc

Now, c corresponds to12 in decimal, so c+1=13 (decimal)=d (hexadecimal)

aef1
34bc
-----
****d

Now we have to add the f and b. There are 15 and 11 decimal, which adds to 26. This is 16*1+10, so is 1a in hexadecimal. Thus, we write down the a and carry the 1.

aef1
34bc
------
****ad

Now we have to add e+4+1 (remember the carry). The hex digit e corresponds to 14, so this adds to 19, which is 16*1+3. We write down the 3 and carry the 1 to get

aef1
34bc
------
**3ad

Finally, we add a+3+1=10+3+1=14, which is e in hex, so the answer is e3ad.

Answer 4

1. If you understand the language of computers (which is the binary system composed of 1 and 0's) youcan easily solve the problem.. But if u simply add the two you'll get 1112022

Answer 5

1)
in base 2
1+1=10
1+1+1= 11

if these numbers in base 2
1 011 011
1 011 011
--------------------
10 110 110

if they are in base 10
the sum is 2 022 022

2)
in base 10
1000a+100e+10f+1+3000+400+10b+c
=1000a+100e+10f+3401+10b+c

Answer 6

1011011 + 1101011 = 100011

aef1 + 34bc = dh84

Answer 7

1. 2112022
2. (aef1) + (34bc)
Dont compare apples and mangoes, bring them to smae platform

Answer 8

neither can i