For example, an imaginary number x + iy, would be located at the point (x , y) on the graph. The real part of an imaginary number ( x ) would be located on the x-axis and the imaginary part would be on the y-axis.
2006-09-29 20:26:49
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answer #1
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answered by Anonymous
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imaginary numbers are values that do not lay on the x-axis or y-axis
for ex:
x^2 + 1
this graph is the same as x^2 - 1, only its been moved 1 unit up instead of down.
2006-09-30 05:36:29
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answer #2
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answered by Sherman81 6
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you can still graph imaginary numbers, you just have to have a correct axis (an imaginary axis). what that person told you was vague and doesn't mean anything. i'd suggest looking up some information on imaginary numbers.
2006-09-29 20:22:53
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answer #3
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answered by twinsfan 2
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the graph that people are used to seeing is a graph of real numbers, so imaginaries don't exist on it
2006-09-29 20:19:55
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answer #4
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answered by Emily 3
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you can graph imaginary numbers but in a different plane. (not in the Cartesian plane)
complex number can be written as a+bi. where a is the real part and bi is the imaginary part. this can be plotted in the complex plane. where the "x-axis" is where you plot the real part and the "y-axis" is where you plot the imaginary part.
2006-09-29 21:17:08
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answer #5
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answered by woof! 2
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That it has complicated zeros skill that the parabola is above the x-axis. y=(x+3)^2 +4 The vertex is (-3,4) and the axis of symmetry is x=-3 the y-intercept is (0,13) the graph additionally is going by (-6,13)
2016-12-12 17:47:06
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answer #6
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answered by dricketts 4
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Well, you'd have the x values on the x-axis and the imaginary number "i" would lie on the y-axis. The only time I had to deal with them was with plotting points like 5+4i would lie at (5,4)
2006-09-29 20:19:42
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answer #7
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answered by MateoFalcone 4
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Wrong. They are what they're called, IMAGINARY.
2006-09-29 20:19:51
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answer #8
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answered by mathlete1 3
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damn math
2006-09-29 20:42:11
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answer #9
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answered by Anonymous
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'x' and 'y'
2006-09-29 20:24:24
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answer #10
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answered by xxxxxx 2
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