An ammeter and a 100ohm resistor are connected in series.A volt meter of 500ohm resistance is connected ......

Question

across the 100ohm resistor .It reads 200V.(i) What is the Internal resistance of the ammeter & (ii) What is the real EMF of the battery.

Answer 1

R = 100*500/600 = 500/6 ohms
I = V/R = 200*6/500 = 12/5 A.

(i)
R = 5*(E-200)/12
(ii)
E = (12/5)R + 200