I really need help on this?

Question

Suppose for this problem that Pr[A | B] = [ 1/5], Pr[A] = [ 1/16], and Pr[B′] = [ 11/16].

(1) What is Pr[B | A]?

(2) What is Pr[B | A′]?

Answer 1

P(A|B) = P(A intersect B)/P(B) = 1/5
P(B) = 1 - P(B') = 1 - 11/16 = 5/16
Back to the first equation.
P(A intersect B)/P(B) = 1/5
P(A intersect B)/(5/16) = 1/5
Multiply both sides by 5/16
P(A intersect B) = (1/5)(5/16)
P(A intersect B) = 1/16
You will also need the formula:
P(B) = P(A intersect B) + P(A' intersect B)
Now you should be able to finish your problems.

Answer 2

if Pr[A] = [ 1/16], and Pr[B′] = [ 11/16].....the

pr[b l a] means divide pr[a] over pr [b] then that would be

pr[b l a]= 11/16 over 1/16 ad that is 1/11

ANSWER IS: 1/11

take care man, i think im not wrong hope it helps u a lot

Answer 3

P(A')=1-1/16=15/16

P(B')=11/16
P(B)=1-11/16
P(B)=5/16

P(A | B)=P(A intersection B) /P(B)
1/5=P(A intersection B)/ (5/16)
1/5*5/16=1/16
P(A intersection B)=1/16

P(A | B)= P(A intersection B)/P(A)
=(1/16) / (1/16)
=1


P(B | A')=P(B intersection A' )/ P(A')

Answer 4

omg is this real or am i dreaming? back in my school i don't even think they had this stuff lol. sorry hon, i can't help you :(