Find the area under the curve given by function f(x) = 2x^4 + 2x^2 + 3 on the interval [-1,2].
Please show all work!
2006-09-29 17:22:20 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
F(x) = 2/5*x^5 +2/3* x^3 + 3x
F(-1) = -2/5 - 2/3 -3
F(2) = 2/5(32)+2/3*8+6
64/5+16/3+6+2/5+2/3+3
= 66/5+18/3+9
= 13 1/5 + 15
= 28 1/5
2006-09-29 17:35:33 · answer #1 · answered by Poncho Rio 4 · 0⤊ 0⤋
Integrate the function.
The antiderivative of f(x) is
(2/5)x^5 + (2/3)x^3 + 3x
Now plug in 2.
Then plug in -1.
Then subtract the two numbers.
That will be your answer.
2006-09-29 17:32:14 · answer #2 · answered by MsMath 7 · 1⤊ 0⤋
hi Mitch. I regarded into both solutions and curiously in case you get d2/dx they both paintings out to be an identical. for this reason, i'd not difficulty about it. i did not take a examine out your calculations. with any success you began out with the quotient rule. yet another element why it would not count number is because you're besides squaring your denominator which cancels out the entire idea of having a thoroughly diverse answer. wish this helped.
2016-11-25 03:28:13 · answer #3 · answered by Anonymous · 0⤊ 0⤋
integrate the function with limits -1 and 2 respectively.....and dont forget that itz first one less second one.
2006-09-30 01:14:58 · answer #4 · answered by sweetfloss8 2 · 0⤊ 0⤋
If it's so simple figure it out yourself. I hope you trust these people because some of them give the wrong answer on purpose.
2006-09-29 17:34:23 · answer #5 · answered by unicornfarie1 6 · 0⤊ 2⤋
simple and calculus is an oxymoron.
2006-09-29 17:29:46 · answer #6 · answered by Canadian Bacon 3 · 1⤊ 2⤋
I have to agree w/ Canadian Bacon!
2006-09-29 17:30:55 · answer #7 · answered by Anonymous · 0⤊ 2⤋