twelve coins group with a faulty coin to be found with arm balance and within three try?

Answer 1

ok.... it will be like this:

first try: weigh the coins by grouping them into 2.... meaning 6 each on the balance....then...perform the second try to which grouping of the coins is lighter

second try: weigh which ever resulting grouping of the coins in the first try, but this time 3 each on the balance, perform the third try on the lighter group

third try: weigh any two coins from the resulting group in the second try .... if the two coins are equal... the one not being weighted is the faulty coin.... if they're unequal then the faulty coin is the lighter one....

*for example

here are the coins....
1 2 3 4 5 6 7 8 9 a b c

First Try:
A - 1 2 3 4 5 6
B - 7 8 9 a b c
result = B is lighter..

Remaining Coins:
7 8 9 a b c

Second Try:
C - 7 8 9
D - a b c
result = D is lighter

Remaining Coins:
a b c

Third Try:
if: a=b, then c is the faulty coin
if: a if: a>b, then b is the faulty coin...

Answer 2

1,2,3,4,5,6 : 7,8,9,10,11,12

1,2,3 : 4,5,6

1:2

If 1 and 2 are even, then 3 is the faulty coin, or if 1 or 2 is the faulty coin.

Answer 3

Narrator: In A.D. 2101, war was beginning.

Captain: What happen ?
Mechanic: Somebody set up us the bomb.
Operator: We get signal.
Captain: What !
Operator: Main screen turn on.
Captain: It's you !!
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CATS: Ha Ha Ha Ha ....
Operator: Captain !!
Captain: Take off every 'Zig' !!
Captain: You know what you doing.
Captain: Move 'Zig'.
Captain: For great justice.