five times the second of three consecutive odd integers is thirtenn less than three times the sum of the first

Question

five times the second of three consecutive odd integers is thirtenn less than three times the sum of the first and thrid integer. find the three consecutive odd intergers


please help me figure this one out.

Answer 1

5*n = 3(n - 2 + n + 2)-13

n-2 =
n =
n+2 =

(solve for n first)

Answer 2

let 'x' be the first odd integer..
thus, x+2 and x+4 are the next two comsecutive integer

(its 'x+2' and 'x+4' because x+1 from an odd integer will give you an even integer)

5 (x+2) = 3 (x+x+4) - 13 ..................... this is the question
5x + 10 = 3x + 3x + 12 -13 .................... opening brackets
5x - 3x - 3x = 12 - 13 - 10 ............ collecting like terms
- x = -11 ........... solving
thus,
x = 11

The other two consecutive odd terms are:

x + 2 = 11 + 2 = 13
and
x + 4 = 11 + 4 = 15

ANS: The three consecutive terms are 11, 13 and 15.

I hope this has helped you understand your question better. Best of luck.

Answer 3

heres the equation...
first #= x
second #= x+2 ((since they must be odd))
third= x+4

5(x+2)=3(x+x+4)-13
distribute:
5x+10=3x+3x+12-13
simplify
5x+10=6x-1
make all x's on one side
11=x

that means the 3 concecutive ODD integers are
11,13,and 17

Answer 4

three odd values are x-2, x, x+2

5x=3(x-2 + x+2) -13
5x = 3(2x) -13
5x = 6x-13
13 + 5x = 6x
13 = x

so x = 13, x+2 = 15, x-2=11

Answer 5

11,13,15