a cricket ball is hit into the air at time t=0. its height, h, above the ground is given by the expression h= 25t - 9.8t^2. what is the value of 't' when the ball lands on the ground?
2006-09-29 15:24:45 · 3 answers · asked by Anonymous in Education & Reference ➔ Homework Help
from eq:
h=25t-9.8t^2
When the ball hits the ground,
h=0
Then the time t when the ball hits the ground is given by:
0=25t-9.8t^2 or 0=t(25-9.8t)
2 solutions possible:
t=0 or t=25/9.8= approx. 2.55 (sec or min depending on the units of the equation)
I would favor t=2.55 since physically we have a given that at t=0, the ball was in the air.
That's my 2-cents solution, hoping that I am not doing the homework for you - I don't like to encourage lazziness
2006-09-29 15:40:25 · answer #1 · answered by pretend-thinker 1 · 0⤊ 0⤋
0=25t-9.8t^2
t=2.551020.................
2006-09-29 22:47:35 · answer #2 · answered by captn_sal 3 · 0⤊ 0⤋
42? see HHGTTG :)
2006-09-29 22:27:42 · answer #3 · answered by want2no 5 · 0⤊ 0⤋