I need of a math wizard?

Question

Is there any really smart person who can help....???? I am trying to figure out if I have 30 numbers from 1-30, how many different sequences of 5 could I make?Please help me....

Answer 1

30 choose 5 = (30!)/[(5!)(25!)] = 142,506
http://en.wikipedia.org/wiki/Binomial_coefficient

Answer 2

The answer Some Dude gave you is correct if you do not care about the order. This is usually referred to as a "Combination" not as a "Sequence."

If you care about the order, the answer is different.

There are 30 ways you can choose the next number and 29 ways you can choose the second number -- since one is taken (so there are 30*29 ways you can choose a 2 number sequence).

The answer to how many sequences you can make is 30*29*28*27*26 -- this is sometimes written as 30!/25!

Answer 3

not sure what you mean by sequences of 5.

if you mean patterns

then you could have

12345
23456
34567 etc

until
25 26 27 28 29 30

there are 26 of those

then you could have

1 3 5 7 9
2 4 6 8 10

then

1 3 6 9 12
2 5 8 11 14

you get the idea i am sure

Answer 4

Well, I think you're asking how many 5-number straights in the 1 to 30 range.

Starting at 1, the first straight includes 1,2,3,4 & 5. So you count from number 5.
At the end, the last straight includes 26, 27, 28, 29 & 30. So you end at number 26.

Between them, you have the numbers 5 thru 26 - which is a group of 22 numbers. (26 - 5 + 1.)

There is your answer: 22 runs of 5 consecutive numbers.

Answer 5

After u upload 3 to both numerator & denominator it turns into x+3/y+3= 5/6 now go multiply u get 6(x+3)=5(y+3) ---->6x-5y+3=0 After 3 is subtracted from fraction x-3/y-3= 7/9 9(x-3)=7(y-3) after simplifying 9x-7y-6=0 now sove both simultaneous equations and get the fee of x and y

Answer 6

30 - just a guess

Answer 7

14.6