6x6. (x-a)(x-b)(x-c)...(x-z)=?

Answer 1

La reputiiiiiiiiisim@ madre, mi viejo tenia razon, en algun momento iba a necesitar saber hablar y leer en ingles

Answer 2

The answer is 0. This is because the third to last term is (x-x) which is equal to 0. We can then rearrange this to 0(x-a)(x-b)...(x-w)(x-y)(x-z), which of course is 0 since anything multiplied by 0.

There is one exception to this and that is seen by writing the product of the terms (x-a)(x-b)...(x-w)(x-y)(x-z) as f(x). We therefore have that the original expression is equal to 0f(x). If
f(x) includes a term with 0 on the denominator of a fraction then 0f(x) contains the term 0/0 which is not defined and hence the product is not 0. This will never be the case if constants a,b,..,w,y,z are constants, which may or may not be rational since the algebraic sums you will be doing will never amount to a fraction with 0 on the denominator. If they are arbitrary functions of x then this result may indeed be possible but is still unlikely and you would probably have to go out of your way to set each function so that a term with a 0 on the denominator exists.

Jez

Answer 3

The answer is 0. Here's why:

(x-a)(x-b)(x-c) does have an answer that is non-zero. And everything up to and including (x-w) will give you a non-zero answer.

However consider this: (x-w)(x-x) = 0

So (x-w)(x-x)(x-y)(x-z) = zero.
Lets use some numbers: 6*6*7*0*8*9:
6*6 = 36
36*7 = 252
252*0 = 0
0*8 = 0
0*9 = 0

Good luck, and remember this; it's an easy extra credit solution on a test.

Answer 4

6x6 = 36

(x-a)(x-b)(x-c)...(x-z)=0
because (x-x) = 0 and any number multiplied by zero results in a zero.

Answer 5

The product is ZERO (0) because we will eventually get the term (x-x)=0 that multiplied by the rest of terms will yield ZERO.

Answer 6

The answer is 0, since in that sequence, the 3rd-last term is (x-x), which is of course, zero.

Answer 7

The answer is 0, because (x-x) = 0.
0 x (the rest of the product) = 0.

Answer 8

Al menos look , de matematico y cientifico si tienes !!

No tuviste tiempo de ir al odontologo, por andar resolviendo esas ecuaciones nucleares, tan extensas y dificiles . = 0.

Ja Ja Ja ja , buena !!

Answer 9

This called an E Q U A T I O N. First, you've got to learn to count, lovely boy.

Answer 10

6x6. (x-a)(x-b)(x-c)...(x-z)=?

6x6.(x-a)(x-b)...(x-x).(x-z)=0

since (x-x)=0 (a1xa2xa3x0 ......x10^10,000,001=0)

iff x remans a member of the alphabet