Chemistry--> How do I calculate the actual size of a cell from one seen on a microscope?

Question

The Biology Department is considering purchasing new microscopes from Schultz Optics. The diameter of the field of view using the high power (40x) objective is 0.35 millimeters (mm). If you were to use this microscope, and under high power found that the longest dimension of a particular cell fills 1/10 of the diameter of the field, what is the size of the cell in reality? Provide your answer in micrometers (um), rounded to the nearest whole number. Do not include units in your answer.

Answer 1

OK, well, if the diameter of the cell 1/10 of the diameter of the field, and the field is 0.35 mm, then wouldn't the diameter of the cell just be 1/10 of 0.35, which is 0.035 mm? And isn't 0.035 millimeters equal to 35 micrometers?

Answer 2

If you know the diameter of the viewing field, you can approximate the size of anything in the field, just as you said. Judge the percentage of the field diameter represented by the object in question, then multiply the field diameter by that percentage. In the example you gave, the size of the cell in mm would be .35/10, or .035 mm, or 35 microns. You can also purchase an inexpensive micrometer that fits into the eyepiece of the microscope, and which, after calibration, will allow you to measure sizes of objects directly.

Answer 3

borrow a grid thingie, and calibrate the microscope screen if there is a TV screen. If there is not, Complain to the management that they need a camera attachment in the specifications of all future scopes..

compare results to all the mathematical formulae you get.
But then, that's Schultz optics (i hope that's a made up name), always the lowest bidder, always the loosest specs.

Answer 4

you can divide the reading of your objective by the power of your lens

Answer 5

search online it will help u