2006-09-29 07:29:22 · 7 answers · asked by Kim K 1 in Science & Mathematics ➔ Mathematics
You have to multiply the term 8pq^2 outside parenthesis by each of the terms inside them:
8pq² * 2pq = 16p²q³
8pq² * (-3p) = -24p²q
8pq² * 5q = 40pq³
Then you just have to add these results:
16p²q³ - 24p²q + 40pq³
That´s it!
Good luck!
2006-09-29 07:40:39 · answer #1 · answered by CHESSLARUS 7 · 0⤊ 0⤋
You multiply each term inside the parentheses by the term in front of the parentheses.
8pq^2(2pq-3p+5q)
16pq^3 - 8pq^2(3p) + 8pq^2(5q)
2006-09-29 20:10:05 · answer #2 · answered by ronw 4 · 0⤊ 0⤋
It is simple if you know the indices laws.
a^x*a^y=a^x+y
8pq^2(2pq-3p+5q)
=16p^2q^3-24p^2q^2+40pq^2
2006-09-29 14:36:16 · answer #3 · answered by openpsychy 6 · 0⤊ 0⤋
=16p^2q^3-24p^2q^2+40pq^3
2006-09-29 14:34:45 · answer #4 · answered by ? 7 · 1⤊ 0⤋
8.2.p.p.q.q^2-8.3.p.p q^2+8.5.p.q.q^2
=16 p^2 . q^3-24p^2q^2+40.p. q^3
2006-09-29 14:35:47 · answer #5 · answered by iyiogrenci 6 · 0⤊ 0⤋
easy
16p^2.q^3-24.p^2.q^2+40p.q^2
2006-09-29 14:38:58 · answer #6 · answered by Seto!! 3 · 0⤊ 0⤋
8pq^2(2pq-3p+5q)
=(8*2)*(p*p)*(q^2*q)+(8*-3)*(p*p)*(q^2)+(8*5)*(p)*(q^2*q)
=16p^2q^3-24p^2q^2+40pq^3
2006-09-29 14:41:34 · answer #7 · answered by D 1 · 0⤊ 0⤋