2006-09-29 03:14:20 · 7 answers · asked by Anonymous in Education & Reference ➔ Homework Help
It's asking to add using the vertical method.
2006-09-29 03:50:19 · update #1
i will give you the answer if you want just ask for it
0
2006-09-29 03:18:26 · answer #1 · answered by AHMED EMAD 5 · 0⤊ 0⤋
5x^2 + 2x - 4
x1= -(√21+1)/5
x2= (√21-1)/5
x^2 – 2x – 3 = (x-3)(x+1)
x1= 3
x2= -1
2x^2 – 4 x – 3
x1= -(√10-2)/2
x2= (√10+2)/2
2006-09-29 03:45:48 · answer #2 · answered by Anonymous · 1⤊ 0⤋
Each equation should be equal to something...Is it 0 or something else?
If all 3 eq are equal to 0 then u apply the next method:
AX^2+Bx+C=0
D=B^2-4AC
X1=[-B-squareroot(D)]/2A
X2=[-B+squareroot(D)]/2A
This gives us the following sollutions:
1ec: X1=-1,165 X2=0,175
2ec:X1=-1 X2=3
3ec: etc
2006-09-29 03:20:31 · answer #3 · answered by Λиδѓεy™ 6 · 0⤊ 0⤋
For the first one: x1= .71652 , x2 =-1.1165.
For the second one: x1 = 3 , x2 = -1
For the third one: x1 = 2.5811, x2-0.58114
remember that for Quadratic equations like these there are always two possibilities.
I've attached the link to the formula machine that helped me give you the answers. It saved my life plenty-a-math class.
2006-09-29 03:16:06 · answer #4 · answered by Kid A 3 · 2⤊ 1⤋
What's the question here?
What are you supposed to be doing with these polynomials?
2006-09-29 03:43:19 · answer #5 · answered by SmileyGirl 4 · 0⤊ 0⤋
Sandra,
What does the question ask you to do with these expressions?
2006-09-29 03:44:52 · answer #6 · answered by LARRY R 4 · 0⤊ 0⤋
http://www.seo99.com/algebrator-beta.htm
Use this link it will be a very big big help to you I promise....
2006-09-29 03:20:23 · answer #7 · answered by monicafranklin2 2 · 0⤊ 0⤋