2X^2 - 4X/X-2
I THINK THIS CANT BE REDUCED ANY MORE.
2006-09-29 03:07:50 · 10 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
You are correct, unless your teacher wants it as a fraction. You should always write it as a fraction, and factor the numerator and denominator completely to make sure it can not be simplified. that is what I did to make sure you were correct.
[2x^2(x-2)-4x]/(x-2)
[2x^3-4x^2-4x]/(x-2)
2x(x^2-2x-2)/(x-2)
Since x^2-2x-2 cannot be factored, there is no common factor for you to cancel and the fraction cannot be simplified further.
2006-09-29 04:33:50 · answer #1 · answered by mom 7 · 0⤊ 0⤋
4X/X=4.
Thus the expression becomes 2X^2-4-2 or 2X^2-6
Divide by 2 and the expression becomes X^2-3
2006-09-29 03:20:30 · answer #2 · answered by Mendelson 2 · 0⤊ 0⤋
The expression is ambiguous. If you mean 2x^2 - (4x/x) - 2, then it can be simplified to 2x^2 - 4 - 2, which is simplified to 2x^2 -6.
If, however, you mean 2x^2 - ( 4x / (x-2) ), it can't be simplified.
2006-09-29 03:22:14 · answer #3 · answered by tevansmd 2 · 0⤊ 0⤋
2x^2-4X/X -2
= 2X^2 -4 -2 ( as 4X/X = 4)
= 2X^2 -6
kindly note how () makes a difference
but if you mean (2X^2-4X)/(X-2) Then () is necessary
numerator = 2x(x-2)
So result = 2x(x-2)/(x-2) = 2x
2006-09-29 03:14:33 · answer #4 · answered by Mein Hoon Na 7 · 0⤊ 0⤋
8d - (-7c - second) = 8d + 7c + second = 7c + 10d to study, Subsitute d = 2, c = 3 into 8d - (-7c - second) 8 x 2 - (-7 x 3 - 2 x 2) = 16 - (-21 - 4) = 16 - (-25) = 16 + 25 = 40-one to study, Subsitute d = 2, c = 3 into 7c + 10d 7 x 3 + 10 x 2 = 21 + 20 = 40-one therefore the equation is ideal. favor this helps.
2016-12-06 09:15:51 · answer #5 · answered by ? 4 · 0⤊ 0⤋
factor out 2x from numerator
2x ( x - (1/(x-2) )
2006-09-29 03:32:34 · answer #6 · answered by Brian D 5 · 0⤊ 0⤋
Ignore the first answer. You were correct....your expression is simplified.
2006-09-29 03:14:55 · answer #7 · answered by Jimmy Crack Corn 2 · 0⤊ 0⤋
(2x^2-4x)/(x-2)=
(2x*(x-2))/(x-2)=
2x
2006-09-29 03:25:47 · answer #8 · answered by Mamad 3 · 0⤊ 0⤋
cant be reduced further...
2006-09-29 03:12:27 · answer #9 · answered by ashwin_hariharan 3 · 0⤊ 0⤋
take common denominator
2x^2(x-2)-4x
---------------
x-2
2x^3-4x^2-4x
-----------------
....x-2
2x(x^2-2x-2)
----------------
...x-2
2006-09-29 03:09:57 · answer #10 · answered by Anonymous · 0⤊ 0⤋