Suppose you have a dense object that won't be much affected by aerodynamics. Then, if you drop it from a known height, "h", the time "t" it takes to fall is given by
h = 0.5 g t^2
or
g = 2h/t^2
2006-09-29 02:55:30
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answer #1
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answered by cosmo 7
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Make a simple pendulum with a string and a small weight.Measure the length L of pendulum (up to centre of weight) and time T (to be more accurate measure 10 times swing and divide by 10).Use formula T=2pi sqt L/g to get g.
2006-09-29 06:32:38
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answer #2
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answered by dwarf 3
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You can try to time the free-fall of an object. It's hard to do unless you have a phototimer. Or you can slow down the process by using a cart on a inclined plane.
2006-09-29 02:53:17
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answer #3
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answered by Alan J 3
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With a simple pendulum
You must to use the formule
T = 2pi square (l/g). You can mueasrure the lengh f the pendulum and the period and obtain g.
2006-09-29 03:48:49
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answer #4
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answered by Juan D 3
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every object falls at 9.8 meters per second. so in two seconds u would be 19.6 meters per second. u acc. 9.8 meters per second squared
2006-09-29 04:53:02
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answer #5
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answered by zerophilmister 2
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g=GMm\r*r,where G is de gravitational constant o earth ,M IS MASS O EARTH ,m is mass o material,r radius o earth.......
2006-09-29 03:04:44
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answer #6
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answered by munis 1
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Munis' answer is rite....
2006-09-29 03:10:32
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answer #7
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answered by questiongirl14 2
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