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the free fall of any material at any sea level

2006-09-29 02:48:45 · 7 answers · asked by scs 1 in Science & Mathematics Physics

7 answers

Suppose you have a dense object that won't be much affected by aerodynamics. Then, if you drop it from a known height, "h", the time "t" it takes to fall is given by

h = 0.5 g t^2

or

g = 2h/t^2

2006-09-29 02:55:30 · answer #1 · answered by cosmo 7 · 0 0

Make a simple pendulum with a string and a small weight.Measure the length L of pendulum (up to centre of weight) and time T (to be more accurate measure 10 times swing and divide by 10).Use formula T=2pi sqt L/g to get g.

2006-09-29 06:32:38 · answer #2 · answered by dwarf 3 · 0 0

You can try to time the free-fall of an object. It's hard to do unless you have a phototimer. Or you can slow down the process by using a cart on a inclined plane.

2006-09-29 02:53:17 · answer #3 · answered by Alan J 3 · 0 0

With a simple pendulum

You must to use the formule

T = 2pi square (l/g). You can mueasrure the lengh f the pendulum and the period and obtain g.

2006-09-29 03:48:49 · answer #4 · answered by Juan D 3 · 0 0

every object falls at 9.8 meters per second. so in two seconds u would be 19.6 meters per second. u acc. 9.8 meters per second squared

2006-09-29 04:53:02 · answer #5 · answered by zerophilmister 2 · 0 0

g=GMm\r*r,where G is de gravitational constant o earth ,M IS MASS O EARTH ,m is mass o material,r radius o earth.......

2006-09-29 03:04:44 · answer #6 · answered by munis 1 · 0 0

Munis' answer is rite....

2006-09-29 03:10:32 · answer #7 · answered by questiongirl14 2 · 0 0

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