x^2 - x - 6
2006-09-29 00:25:40 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
The general format for such expressions is
x^2 + (a+b)x + a*b
This can be factorized as x^2 + ax + bx +a*b = x(x+a) + b(x+a)
= (x+a)*(x+b)
Now here,
a+b = -1 and a*b = -6
By trail and error we get a=-3 and b=2
Substituting we get,
x^2 - x -6 = (x-3)*(x+2)
Thus is factorized
2006-09-29 01:58:18 · answer #1 · answered by anjali 2 · 1⤊ 0⤋
x^2-x-6 =
(x+2)(x-3)
2006-09-29 09:09:40 · answer #2 · answered by Anonymous · 1⤊ 0⤋
If a trinomial can be factored it will be the product of two binomials. The first term of each must multiply to be x^2, so each must be x
(x +/- ? )(x +/-?)
the second term of each must multiply to be -6, so it's either +3 times -2 or -3 times +2, but their sum must be -1, so the latter is correct. This 'trick' only works if teh coefficient of the first term is 1.
(x-3)(x+2)
2006-09-29 12:23:01 · answer #3 · answered by mom 7 · 0⤊ 0⤋
FACTOR is the correct term and the other answers are correct.
FOIL is when you take (x-3)(x+2) and multiply it out to get x^2-x-6
2006-09-29 07:56:37 · answer #4 · answered by MollyMAM 6 · 1⤊ 0⤋
x² - x - 6
(x - 3) (x + 2)
- - - - - - - - - - - - - - - -
Check
(x - 3)(x + 2) = x² -3x +2x - 6 = x² - x - 6
2006-09-29 10:09:03 · answer #5 · answered by SAMUEL D 7 · 1⤊ 0⤋
This is FOIL or at least thats what we call it here: (x+2)(x-3)
2006-09-29 07:29:01 · answer #6 · answered by hayharbr 7 · 0⤊ 0⤋
(x-3)(x+2) I is actually backwards foiling.
2006-09-29 07:33:26 · answer #7 · answered by Sarah Beth 3 · 0⤊ 0⤋